by Willard » Sun Nov 03, 2013 9:04:53 pm
I think we can do this fairly strategically. IDC who picks our five peeps, but this is the strategy we should use to figure out their combination.
Step #1. For your first attempt, select one color, then put four of those pegs on the board. (If you like red, play R-R-R-R.)
Your opponent will then have to indicate whether or not any red pieces are in the solution. If he/she does not put down any pegs, that means there are no red pegs in the solution, and you do not have to guess red for the remainder of the game.
However, if there are red pegs in the solution, he will have to tell you how many there are.
Step #2. If you get no pegs for the first attempt, select another color, and put four of those pegs on the board for your second attempt.
However, say for instance, you know from your first attempt that there is one red peg in the solution. Your second guess will accomplish two purposes: 1) try to guess the position of the red peg, and 2) try to determine if the next color is present in the solution.
Put the red peg in the first position, then select another color (orange) and fill the remaining three positions. The incremental change in the total number correct is the count of orange pegs in the solution. (If your opponent puts down 1 indicator for the first step, and 3 for the second step, you know that there are two orange pegs (three minus one) in the solution. If there is still only one indicator for the second step, there are zero orange pegs (one minus one) in the solution.)
Another clue can be distilled by counting the number of white pegs (right color, wrong position) your opponent puts out. Say, for instance, that in step #1, you found out that there is one red peg. In step #2, if your opponent puts out zero white pegs, you know that the red peg is in the correct position. If he puts out one white peg, you know that the red peg is in the wrong position. If he puts out two white pegs, you know that the orange peg belongs in the place that the red peg is currently in.
Step #3: Basically, step #3 is similar to step #2. At this point, you will know how many red and orange pieces belong in the solution. Move on to the next color (if necessary) and make another guess. If you know there is one red and one orange piece, put a red, an orange, and two yellows, and try to guess the position of the red and orange. If there is one orange piece and zero red pieces, try one orange and three yellows.
After step #3, you just keep trying to determine the color components and the order of these components. Just repeat step #3, but use your additional knowledge to make further deductions.
I don't know if I am making myself clear or not, but here is the intent of this strategy:
Part 1 - find out what colors are in the solution, and in what quantity.
Part 2 - find out the order of the colors in the solution
If you can combine parts 1 and 2, you will come up with the strategy I have outlined above.